Scientists have developed a type of panel that can generate electricity from rain,
by keeping some of the motion energy in the raindrops that hit the panel
converted to electrical energy.

a) I tested the research loop and easily killed 100 microliters from one
height of 15 cm above the panel, and measured that it can generate an electrical energy
at 3.24 uJ. What percentage of the motion energy of the kill is converted
for electrical energy? Disregard the air resistance
B) Suppose a typical rain shower consists of almost spherical raindrops
with a radius of 1.7 mm. (These have less volume than those in the previous sub-question.)
For drops that fall from high altitude we can no longer ignore
air resistance. It is given by the formula
——1/2*lv*2CDr2
there l = 1.23 kg / m3
is the density of the air, v is the speed of the kill, r is the radius
to the kill and CD = 0.7 is a constant. What is the greatest speed and death will
get, terminal speed, as it falls through the air? How much kinetic energy
does every one have a kill?

c) I am heavy rainfall falling 10 mm of rain at once. This is equivalent to 135
raindrops per square meter per second. What effect will they have from these?
the panels in a heavy rain shower? Compare your answer with the typical one
efficient from a solar panel that is around 150-200 W / m2